I'm new to R and learning it via Coursera and during one of the assignments outline in this pdf I encountered the following error:

Error in split.default(x = seq_len(nrow(x)), f = f, drop = drop, ...) :   
group length is 0 but data length > 0
Basically I'm stuck in part 2 Finding best Hospital in the state part, and while writing function for it I test its constructs via console. So far to test it I wrote this piece of code:
outcome <- read.csv("outcome-of-care-measures.csv", colClasses = "character")
outcome[, 11] <- as.numeric(outcome[, 11]) # 30-day mortality for the heart attack
outcome[, 17] <- as.numeric(outcome[, 17]) # 30-day mortality for the heart failure 
outcome[, 23] <- as.numeric(outcome[, 23]) # 30-day mortality for the pneumonia 
outcome <- outcome[, c(2, 7, 11)] # Subsetting three columns
outcome <- na.omit(outcome) # omitting na
names(outcome) <- c("hospital", "state", "outcome") #Renaming the columns
outcome <- split(outcome, outcome$State) # Splitting it based on states
I'm also attaching the Hospital Sample
Hope anyone can point me in the right direction.
                          hospital state outcome
1 SOUTHEAST ALABAMA MEDICAL CENTER    AL    14.3
2    MARSHALL MEDICAL CENTER SOUTH    AL    18.5
3   ELIZA COFFEE MEMORIAL HOSPITAL    AL    18.1
you named it state, and then tried to split on a column called State. R is case sensitive.
Related Solutions
Python – How to split a list into evenly sized chunks

Here's a generator that yields the chunks you want:
def chunks(lst, n):
    """Yield successive n-sized chunks from lst."""
    for i in range(0, len(lst), n):
        yield lst[i:i + n]
import pprint
pprint.pprint(list(chunks(range(10, 75), 10)))
[[10, 11, 12, 13, 14, 15, 16, 17, 18, 19],
 [20, 21, 22, 23, 24, 25, 26, 27, 28, 29],
 [30, 31, 32, 33, 34, 35, 36, 37, 38, 39],
 [40, 41, 42, 43, 44, 45, 46, 47, 48, 49],
 [50, 51, 52, 53, 54, 55, 56, 57, 58, 59],
 [60, 61, 62, 63, 64, 65, 66, 67, 68, 69],
 [70, 71, 72, 73, 74]]
If you're using Python 2, you should use xrange() instead of range():
def chunks(lst, n):
    """Yield successive n-sized chunks from lst."""
    for i in xrange(0, len(lst), n):
        yield lst[i:i + n]
Also you can simply use list comprehension instead of writing a function, though it's a good idea to encapsulate operations like this in named functions so that your code is easier to understand. Python 3:
[lst[i:i + n] for i in range(0, len(lst), n)]
Python 2 version:
[lst[i:i + n] for i in xrange(0, len(lst), n)]
    
Bash – How to split a string on a delimiter in Bash

You can set the internal field separator (IFS) variable, and then let it parse into an array. When this happens in a command, then the assignment to IFS only takes place to that single command's environment (to read ). It then parses the input according to the IFS variable value into an array, which we can then iterate over.
This example will parse one line of items separated by ;, pushing it into an array:
IFS=';' read -ra ADDR <<< "$IN"
for i in "${ADDR[@]}"; do
  # process "$i"
This other example is for processing the whole content of $IN, each time one line of input separated by ;:
while IFS=';' read -ra ADDR; do
  for i in "${ADDR[@]}"; do
    # process "$i"
done <<< "$IN"