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Hi someone tell me what is the difference between using -c and -e in a LFTP script?

e.g. of -c: Lftp default timeout and retry?

e.g. of -e: https://stackoverflow.com/a/32432851/13862759

Can someone point me to where it is in the manual? https://lftp.yar.ru/lftp-man.html

I would like to know in what situations it is correct to use -c, -e or nothing.

[...] -c commands Execute the given commands and exit. Commands can be separated with a semicolon, `&&' or `||'. Remember to quote the commands argument properly in the shell. This option must be used alone without other arguments (except --norc)

The lftp command has an interactive mode. If you use -c , the lftp will exit without starting this interactive mode. If you use -e , then it won't exit, and you can continue running commands manually. So you could use -e for running some initial setup and then use the interactive mode to do whatever you actually wanted to do (though you could also use the --rcfile option for this).

For examples of -e , you might have aliases like:

alias lftp_debug='lftp -e "debug -o lftp-debug-output 3"'
alias lftp_no_cahce='lftp -e "set cache:enable false"
For -c, basically any time you have a complete set of commands to execute with lftp with no further manual input to be provided, you can use -c. You don't need to use exit like the example answer you linked to, since lftp will automatically exit anyway.