$results = User::where('this', '=', 1)
    ->where('that', '=', 1)
    ->where('this_too', '=', 1)
    ->where('that_too', '=', 1)
    ->where('this_as_well', '=', 1)
    ->where('that_as_well', '=', 1)
    ->where('this_one_too', '=', 1)
    ->where('that_one_too', '=', 1)
    ->where('this_one_as_well', '=', 1)
    ->where('that_one_as_well', '=', 1)
    ->get();

是否有比这更好的实现方式吗？

在 Laravel 5.3 你可以传递一个 wheres 数组:

$query->where([
    ['column_1', '=', 'value_1'],
    ['column_2', '<>', 'value_2'],
    [COLUMN, OPERATOR, VALUE],
自2014年6月起，你可以将数组传递给 where，
只要你想要所有 wheres 使用 and 运算符，你就可以用这种方式对它们进行分组：
$matchThese = ['field' => 'value', 'another_field' => 'another_value', ...];
// 如果你需要 or where 语句，同理:
$orThose = ['yet_another_field' => 'yet_another_value', ...];
$results = User::where($matchThese)->get();
// with another group
$results = User::where($matchThese)
    ->orWhere($orThose)
    ->get();
上面代码的查询语句如下:
SELECT * FROM users
  WHERE (field = value AND another_field = another_value AND ...)
  OR (yet_another_field = yet_another_value AND ...)
查询作用域可以帮助你把代码变的更具可读性。
《Laravel 中文文档》
在你的模型中，创建像这样的作用域方法:
public function scopeActive($query)
    return $query->where('active', '=', 1);
public function scopeThat($query)
    return $query->where('that', '=', 1);
然后，你就可以在构建查询时调用此方法：
$users = User::active()->that()->get();
            where
                                
参考：https://stackoverflow.com/questions/1932...
    public function testInfo(){
        $id=1;
        TableOne::whereHas('linkTableTwo',function($query) use ($id){
           $query->where('id',$id);
        })->with('linkTableTwo')->get();
    
用了下面的这个，但是效果不太对
User::where(['id' => 1, 'sex' => 0])->orWhere(['id' => 2, 'sex' => 1])->get();
array:1 [▼
  0 => array:3 [▼
    "query" => "select * from `bl_users` where (`id` = ? and `sex` = ?) or (`id` = ? or `sex` = ?)"
    "bindings" => array:4 [▶]
    "time" => 3.11
我是想要这样的效果
"select * from `bl_users` where (`id` = ? and `sex` = ?) or (`id` = ? and `sex` = ?)"
这样的怎么可以实现