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#include <opencv2\core\core.hpp>
#include<opencv2\imgproc\imgproc.hpp>
#include<opencv2\highgui\highgui.hpp>
#include <iostream>
#include<conio.h>
using namespace cv;
using namespace std;
int main()
Mat im= imread("D:\\try.jpg"),newface,A;
Mat im2 = imread("D:\\project\\barc\\variables\\Eigenface.jpg");
cvtColor(im, im, CV_BGR2GRAY);
cvtColor(im2, im2, CV_BGR2GRAY);
resize(im, im, Size(48, 48));
newface = im.reshape(0, 2304);
newface.convertTo(newface, CV_32FC1);
im2.convertTo(im2, CV_32FC1);
cout << "Diff : " << newface.size() << "\t" << "channels" << newface.channels() <<  endl;
cout << "Eigen : " << im2.size() << "\t" << "channels" << im2.channels() << endl;
A = im2*newface.t();
_getch();
return 0;
The Eigenface.jpg is of dimension (9x2304). When i am multiplying with the image i am facing this error is coming can anyone help?
                Can you post the code? the construction of the matrix? If Eigenface is 2304x1 then that is the problem...
– sop
                Aug 19, 2014 at 7:51
                I have two matrix :  M1 has size (9x2304)   M2 has size (1x2304)   i have performing calculation  M3 = M1*(M2.t())  Is it wrong?
– user3322848
                Aug 19, 2014 at 10:30
                no idea, what you're doing now. again, the rule is simple:  col-Vec * Matrix, or Matrix * row-Vec
– berak
                Aug 19, 2014 at 10:43
Print matrix width (cols) and height (rows) and see the problem: Eigenface.cols = 9 and diff_test_image.rows = 2304. The two must be equal to do the multiplication. Do:
test_omega = (Eigenface.t())*diff_test_image;
Edit after code:
What does it prints in the line of cout << "Diff : " << newface.size() << "\t" << "channels" << newface.channels() <<  endl; ? What about the next one? Is the Eigenface.jpg of size 9x2304? I do not think so...
Even if im2.rows == 2304, you are multiplying with a column vector that should be in front of im2 or just try newface = im.reshape(0, 1); for having a column vector so it's transpose will be a row vector
        
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