上面 excelReader.read(new Sheet(1, 1, Object.class)); 方法报错

非常抱歉，我在之前的回答中犯了一个错误。EasyExcel库中的Sheet类确实是抽象的，不能直接实例化。正确的用法是使用它的Builder类来创建Sheet[对象](https://geek.csdn.net/educolumn/04c51611e4b730957464192e0307b82c?spm=1055.2569.3001.10083)，如下所示： ```java public st[ati](https://geek.csdn.net/educolumn/150d7073277950db5f09620704e791cf?spm=1055.2569.3001.10083)c List<Object> readExcelToList(MultipartFile file) throws IOException { List<Object> list = new ArrayList<>(); InputStream inputStream = file.[get](https://geek.csdn.net/educolumn/31aebce56f4ecc5451aac3a194ff6259?spm=1055.2569.3001.10083)InputStream(); ExcelReader excelReader = EasyExcel.read(inputStream, new AnalysisEventListener<Object>() { @Override public void invoke(Object data, AnalysisContext context) { list.add(data); @Override public void doAfterAl[lan](https://geek.csdn.net/educolumn/2e627c1ce792f2bd6c896ec0221f0ac0?spm=1055.2569.3001.10083)alysed(AnalysisContext context) { // 解析结束销毁不用的资源 try { context.readWorkbookHolder().[get](https://geek.csdn.net/educolumn/31aebce56f4ecc5451aac3a194ff6259?spm=1055.2569.3001.10083)InputStream().close(); ```