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https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#comment_2850967

https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#comment_2850977

https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#answer_207049

You simply have to go back to the definition of odd and even. An (integer) number is even if it is divisible by 2, odd otherwise. Divisible by 2 means that the remainder when divided by 2 is 0. That is easy to test, the function to get the remainder is (or you can use ). As with many things in matlab you do not need a loop, the functions work on vector / matrices

        
          m = [1 2 3;4 5 6];
         
          iseven = rem(m, 2) == 0;

Mathworks Support Staff Comments

Depending on the usage, you can use "rem" or "mod" to check if a number is divisible by 2. The "r = rem(a,b)" function finds the remainder after division of a by b, where the sign of the remainder r follows the sign of a. Meanwhile, the "r = mod(a,b)" function finds the remainder after division of a by b, where the sign of the remainder r follows the sign of b.

For example, if you have a matrix of integer numbers that are positive only, you can find the even or odd numbers by first finding the matrix indices of these elements using "rem":

        
          m = [1 2 3; 4 5 6]
         
          iseven = rem(m,2) == 0;
         
          m_even = m(iseven)
         
          isodd = rem(m,2) == 1;
         
          m_odd = m(isodd)

If you want to execute some statements based on whether the positive number in m is even or odd, you can make a conditional statement within a “for” loop:

        
          for
         
          i = 1:numel(m)
         
          if
         
          rem(m(i),2) == 0
         
          % statements to execute for even m(i)
         
          else
         
          % statements to execute for odd m(i)
         
          end
         
          end

Otherwise, if you have a matrix of integer numbers that can be negative in general, use "mod" instead of "rem" in the above example.

https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#answer_345229

you can also calculate the remainder after the division. b = mod(a,m) returns the remainder after division of a by m, where a is the dividend and m is the divisor. This function is often called the modulo operation, which can be expressed as b = a - m.*floor(a./m). The mod function follows the convention that mod(a,0) returns a.

by dividing by two, the remainder is either 1 or 0. For odd numbers, the remainder will be 1, and for even, it will be 0. Just be sure to use "==" for a true/false response when querying.

      
        m=1
       
        if
       
        mod(m,2) == 1
       
        else
       
        end

https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#answer_447779

https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#answer_424993

https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#answer_498967

An even number is a number which has a remainder of 0 upon division by 2, while an odd number is a number which has a remainder of 1 upon division by 2.

If the units digit (or ones digit) is 1,3, 5, 7, or 9, then the number is called an odd number , and if the units digit is 0, 2, 4, 6, or 8, then the number is called an even number (for the set of numbers 0-9). Thus, the set of integers can be partitioned into two sets based on parity:

the set of even (or parity 0) integers
the set of odd (or parity 1) integers.

**Parity is a fundamental property of integers, and many seemingly difficult problems can be solved by making parity arguments.

The below function is to find the details of even and odd number in a given list

      
        function
       
        [sum_even,sum_odd,n_even,n_odd] = even_odd(x)
       
        sum_even = 0;
       
        % initialization of sum of even numbers in the given list
       
        sum_odd = 0;
       
        % initialization of sum of odd numbers in the given list
       
        n_even = 0;
       
        % initialization of total even numbers in the given list
       
        n_odd = 0;
       
        % initialization of total odd numbers in the given list
       
        for
       
        i=1:1:x
       
        % start of the list
       
        if
       
        mod(i,2)==0
       
        sum_even=sum_even+i;
       
        % sum of the even numbers
       
        n_even=n_even+1;
       
        % % increase sum of even number by 1
       
        else
       
        sum_odd=sum_odd+i;
       
        % sum of the odd numbers
       
        n_odd=n_odd+1;
       
        % increase sum of even number by 1
       
        end
       
        end

Example set for list:1,2,3,4,5,6,7,8,9,10

sum_even = 30, which is 2+4+6+8+10 = 30

sum_odd = 25 , which is 1+3+5+7+9 = 25

n_even = 5, which are 2,4,6,8,10

n_odd = 5, which are 1,3,5,7,9

I hope this helps.

https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#answer_424676

https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#answer_989930

https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#answer_1076608

https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#comment_3108151

Yeah, but why use loops? Why use literal numeric assignments? It can all be done in one line, for any size array, and the output is more useful, since it can directly be used for indexing.

x = 1:10

x = 1x10

1 2 3 4 5 6 7 8 9 10

isodd = logical(mod(x,2)) % true when odd

isodd = 1x10 logical array

1 0 1 0 1 0 1 0 1 0

https://www.de.mathworks.com/matlabcentral/answers/264769-odd-and-even-numbers#answer_1500119

You can solve this problem using a loop and an if-else statement to check whether a number is odd or even.

% Define the range of numbers to check

startNum = 1; % Starting number

endNum = 10; % Ending number

% Loop through each number in the range

for num = startNum:endNum

% Check if the number is even

if mod(num, 2) == 0

fprintf( '%d is even\n' , num);

else

fprintf( '%d is odd\n' , num);

end

1 is odd

2 is even

3 is odd

4 is even

5 is odd

6 is even

7 is odd

8 is even

9 is odd

10 is even

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