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oid= $Response | grep -Po '"oid": *\K"[^"]\*"'

{
"count": 1,
"items": [{
        "oid": "xyzxyzxyzxyzxyzxyzxyz",
        "creationDate": "2019-02-05T02:21:08.662+0000"
}

echo "$Response" | grep -ozP '(^|\n){\n"count":\s+[0-9]+,\n"items":\s+\[{\n\s+"oid":\s+"\K[^"]*'

(^|\n){\n    ##Matching new line OR starting here followed by { and new line.
"count":\s+  ##Matching "count": followed by 1 or more spaces.
[0-9]+,\n    ##Matching 1 or more digits followed by comma followed by new line.
"items":\s+  ##Matching "items": followed by 1 or more spaces.
\[{\n\s+     ##matching literal [ followed by { new line and spaces.
"oid":\s+"   ##Matching "oid": followed by 1 or more spaces followed by " here.
\K           ##Here is GNU grep's GREAT option \K which helps us to forget previous match.
             ##Basically match everything but forget its value so that we can get only required values.
[^"]*        ##Match everything just before next occurrence of " here.

Response='
"count": 1,
"items": [{
        "oid": "xyzxyzxyzxyzxyzxyzxyz",
        "creationDate": "2019-02-05T02:21:08.662+0000"

问 (Linux)具体使用Grep提取JSON值(没有json解析器) EN

回答 2

Stack Overflow用户

Stack Overflow用户