在springboot框架下怎么将ZipOutputStream写入到HttpServletResponse的ServletOutputStream中
43浏览 · 2024-03-02 15:53:43
在 Spring Boot 框架中，将 ZipOutputStream 写入到 Http[servlet](https://geek.csdn.net/educolumn/0962c1b81c0009696a8cedc823c947da?spm=1055.2569.3001.10083)Response 的 [servlet](https://geek.csdn.net/educolumn/0962c1b81c0009696a8cedc823c947da?spm=1055.2569.3001.10083)OutputStream 中的步骤如下：
1. 获取 HttpServletResponse [对象](https://geek.csdn.net/educolumn/04c51611e4b730957464192e0307b82c?spm=1055.2569.3001.10083)。
```java
@GetMapping("/downloadZip")
public void downloadZip(HttpServletResponse response) throws IOException {
// 设置响应头信息
response.setContentType("application/zip");
response.setHeader("Content-Dis[pos](https://geek.csdn.net/educolumn/0399089ce1ac05d7729a569fd611cf73?spm=1055.2569.3001.10083)ition", "attachment; filename=file.zip");
// 获取 ServletOutputStream
ServletOutputStream out = response.getOutputStream();
// 创建 ZipOutputStream [对象](https://geek.csdn.net/educolumn/04c51611e4b730957464192e0307b82c?spm=1055.2569.3001.10083)
ZipOutputStream zipOut = new ZipOutputStream(out);
// 将文件写入到 ZipOutputStream 中，此处省略具体实现
// ...
// 关闭 ZipOutputStream 和 ServletOutputStream
zipOut.close();
out.close();
2. 设置响