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link管理  ›  Solved: Problem in yahoo weather - PTC Community
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https://community.ptc.com/t5/ThingWorx-Developers/Problem-in-yahoo-weather/td-p/529545
失落的金鱼
11 月前

Hello Expert ,

I am getting this error on get yahoo weather :

If you know the solution for this error please suggest me.@

Execution error in service script [WeatherThing GetWeather] : Wrapped org.xml.sax.SAXParseException; lineNumber: 1; columnNumber: 429; The content of elements must consist of well-formed character data or markup. Cause: The content of elements must consist of well-formed character data or markup.

Code :

var stringLocation=location+" ";

var arrayLocations=stringLocation.split(",");

var lat=arrayLocations[0];

var long=arrayLocations[1];

//Modify the open weather url here if you are using your own API key

var params = {

url: " http://api.openweathermap.org/data/2.5/forecast?lat= "+lat+"&lon="+long+ "&units=imperial" +"&type=accurate&mode=xml&APPID=4abc8a3c9f101ccf9c7cfe7cbf3dfed7" /* STRING */,

timeout: 60 /* NUMBER */

};

// result: XML

var xmlPage = Resources["ContentLoaderFunctions"].LoadXML(params); // Error Generate on This line

var params = {

infoTableName : "InfoTable",

dataShapeName : "OpenWeatherFeed"

};

// CreateInfoTableFromDataShape(infoTableName:STRING("InfoTable"), dataShapeName:STRING):INFOTABLE(YahooWeatherFeed)

var result = Resources["InfoTableFunctions"].CreateInfoTableFromDataShape(params);

var from_today_value=xmlPage.forecast.time[0][email protected](0,10);

logger.warn("from_today_value= "+from_today_value);

for each (var item in xmlPage.forecast.time) {

var row = new Object();

var [email protected](0,10);

if(from_current_value!=from_today_value){

row.WindDirection = item.windDirection.@name;

row.WindSpeed=item.windSpeed.@mps;

row.WeatherTemp=parseFloat(item.temperature.@value);

row.WeatherHumidity=parseFloat(item.humidity.@value);

row.From=item.@from;

row.To=item.@to;

row.Title=xmlPage.location.name+" "+xmlPage.location.country;

row.Precipitation=(item.precipitation.@type+" "+item.precipitation.@value)==" "?"No Precipitation":item.precipitation.@type;

result.AddRow(row);

}

}

Thanks ,

Mayank

Hi Mayank,

Yahoo Weather API is no longer in service. Please use OpenWeatherMap as a replacement or Wunderground API.

Below is an implementation for a  OpenWeatherMap API service call:

var stringLocation = location + " " ;

var arrayLocations = stringLocation . split ( "," );

var lat = arrayLocations [ 0 ];

var long = arrayLocations [ 1 ];

var params = {

url : " http://api.openweathermap.org/data/2.5/forecast?lat= " + lat + "&lon=" + long + "&units=metric&type=accurate&mode=xml&APPID=4abc8a3c9f101ccf9c7cfe7cbf3dfed7" /* STRING */ ,

timeout : 160 /* NUMBER */

};

// result: XML

var xmlPage = Resources [ "ContentLoaderFunctions" ]. LoadXML ( params );

var params = {

infoTableName : "InfoTable" ,

dataShapeName : "OpenWeatherFeed"

};

var result = Resources [ "InfoTableFunctions" ]. CreateInfoTableFromDataShape ( params );

var from_today_value = xmlPage . forecast . time [ 0 ] . @from . substring ( 0 , 10 ) ;

  1. logger . warn ( "from_today_value= " + from_today_value );

for each ( var item in xmlPage . forecast . time ) {

var row = new Object ();

var from_current_value = item . @from . substring ( 0 , 10 ) ;

row . WindDirection = item . windDirection . @name ;

row . WindSpeed = item . windSpeed . @mps ;

row . WeatherTemp = parseInt ( item . temperature . @value );

row . WeatherHumidity = parseFloat ( item . humidity . @value );

row . From = item . @from ;

row . To = item . @to ;

row . Title = xmlPage . location . name + " " + xmlPage . location . country ;

row . Precipitation =( item . precipitation . @type + " " + item . precipitation . @value )== " " ? "NoPrecipitation" : item . precipitation . @type ;

result . AddRow ( row );

}


Here are the inputs and outputs of the service

Please let me know if you are in need of anything else.

Thank you,

Veronica

Hi Mayank,

Yahoo Weather API is no longer in service. Please use OpenWeatherMap as a replacement or Wunderground API.

Below is an implementation for a  OpenWeatherMap API service call:

var stringLocation = location + " " ;

var arrayLocations = stringLocation . split ( "," );

var lat = arrayLocations [ 0 ];

var long = arrayLocations [ 1 ];

var params = {

url : " http://api.openweathermap.org/data/2.5/forecast?lat= " + lat + "&lon=" + long + "&units=metric&type=accurate&mode=xml&APPID=4abc8a3c9f101ccf9c7cfe7cbf3dfed7" /* STRING */ ,

timeout : 160 /* NUMBER */

};

// result: XML

var xmlPage = Resources [ "ContentLoaderFunctions" ]. LoadXML ( params );

var params = {

infoTableName : "InfoTable" ,

dataShapeName : "OpenWeatherFeed"

};

var result = Resources [ "InfoTableFunctions" ]. CreateInfoTableFromDataShape ( params );

var from_today_value = xmlPage . forecast . time [ 0 ] . @from . substring ( 0 , 10 ) ;

  1. logger . warn ( "from_today_value= " + from_today_value );

for each ( var item in xmlPage . forecast . time ) {

var row = new Object ();

var from_current_value = item . @from . substring ( 0 , 10 ) ;

row . WindDirection = item . windDirection . @name ;

row . WindSpeed = item . windSpeed . @mps ;

row . WeatherTemp = parseInt ( item . temperature . @value );

row . WeatherHumidity = parseFloat ( item . humidity . @value );

row . From = item . @from ;

row . To = item . @to ;

row . Title = xmlPage . location . name + " " + xmlPage . location . country ;

row . Precipitation =( item . precipitation . @type + " " + item . precipitation . @value )== " " ? "NoPrecipitation" : item . precipitation . @type ;

result . AddRow ( row );

}


Here are the inputs and outputs of the service

Please let me know if you are in need of anything else.

Thank you,

Veronica

Hi Veronica,

this code is for forecast in weather application, is possible to get code for actual weather in same application? If I am wrong please correct me.

http://openweathermap.org/forecast5 Here you use this, it's for forecast in 3 hours interval

http://openweathermap.org/current

And i would like to get data from this page if it is possible.

So i would like exchange yahoo weather for this one:YahooWeatherFeed.

Thank you for any reply,

Robert

Hi Robert,

Indeed, the code I posted is for retrieving forecast data. You can use the  Rest call described in the tutorial link you mentioned .

The parsing of the data once you get it in your thingworx service will be different from the one did for the forecast call. Let me know if you are experiencing problems with parsing it.

Thank you,

Veronica

Hi,

I'm still having an error message of

  • org.xml.sax.SAXParseException; lineNumber: 1; columnNumber: 1; Content is not allowed in prolog Cause: Content is not allowed in prolog

I guess it's related to this issue

( Mark S. Kolich - Java: Resolving org.xml.sax.SAXParseException: Content is not allowed in prolog )

But I have no idea how to modify the code

Here is the code

var stringLocation=location+" ";

var arrayLocations=stringLocation.split(",");

var lat=arrayLocations[0];

var long=arrayLocations[1];

var params = {

url: " http://api.openweathermap.org/data/2.5/forecast?lat= "+lat+"&lon="+long+"&units=metric&type=accurate&mode=xml&APPID=ff07c7c18d3a5d86f13a93134f1d94a9" /* STRING */,

timeout: 160 /* NUMBER */

};

// result: XML

var xmlPage = Resources["ContentLoaderFunctions"].LoadXML(params);

var params = {

infoTableName : "InfoTable",

dataShapeName : "OpenWeatherFeed"

};

var result = Resources["InfoTableFunctions"].CreateInfoTableFromDataShape(params);

var from_today_value=xmlPage.forecast.time[0][email protected](0,10);

logger.warn("from_today_value= "+from_today_value);

for each (var item in xmlPage.forecast.time) {

var row = new Object();

var [email protected](0,10);

row.WindDirection = item.windDirection.@name;

row.WindSpeed=item.windSpeed.@mps;

row.WeatherTemp=parseInt(item.temperature.@value);

row.WeatherHumidity=parseFloat(item.humidity.@value);

row.From =  item.@from;

row.To =  item.@to;

row.Title=xmlPage.location.name+" "+xmlPage.location.country;

row.Precipitation=(item.precipitation.@type+" "+item.precipitation.@value)==" "?"NoPrecipitation":item.precipitation.@type;

result.AddRow(row);

}

Thank you.

Hello Lee ,

Take input parameter as a Location ,

var test=Location+" ";

var arrayLocations=test.split(",");

var lat=arrayLocations[0];

var long=arrayLocations[1];

var prm = {

url : " http://api.openweathermap.org/data/2.5/forecast?lat= "+lat+"&lon="+long+"&units=metric&type=accurate&mode=xml&APPID=4abc8a3c9f101ccf9c7cfe7cbf3dfed7",

timeout: 160 /* NUMBER */

};

var xmlPage = Resources["ContentLoaderFunctions"].LoadXML(prm);

// result: XML

var params = {

infoTableName : "InfoTable",

dataShapeName : "OpenWeatherFeed"

};

var result = Resources["InfoTableFunctions"].CreateInfoTableFromDataShape(params);

var from_today_value=xmlPage.forecast.time[0][email protected](0,10);

logger.warn("from_today_value= "+from_today_value);

for each (var item in xmlPage.forecast.time) {

var row = new Object();

var [email protected](0,10);

row.WindDirection = item.windDirection.@name;

row.WindSpeed=item.windSpeed.@mps;

row.WeatherTemp=parseInt(item.temperature.@value);

row.WeatherHumidity=parseFloat(item.humidity.@value);

row.From =  item.@from;

row.To =  item.@to;

row.Title=xmlPage.location.name+" "+xmlPage.location.country;

//  row.Precipitation=(item.precipitation.@type+" "+item.precipitation.@value)==" "?"NoPrecipitation":item.precipitation.@type;

result.AddRow(row);

}

Thanks ,

Mayank

Hello Im have a diferent error mi code is

// Need to make a free wunderground.com account to get this key

var apiKey = "381603bc1002b5ce";

var temperature;

var humidity;

//Inputted location needs to be valid lat, long: 40.7127, 74.0059

if(location != null){

var test=location+" ";

var arrayLocations=test.split(",");

var lat=arrayLocations[0];

var long=arrayLocations[1];

var prm = {

url : " http://api.openweathermap.org/data/2.5/forecast?lat= "+lat+"&lon="+long+"&units=metric&type=accurate&mode=xml&APPID=4abc8a3c9f101ccf9c7cfe7cbf3dfed7",

timeout: 160 /* NUMBER */

};

var xmlPage = Resources["ContentLoaderFunctions"].LoadXML(prm);

// result: XML

var params = {

infoTableName : "InfoTable",

dataShapeName : "OpenWeatherFeed"

};

var result = Resources["InfoTableFunctions"].CreateInfoTableFromDataShape(params);

var from_today_value=xmlPage.forecast.time[0][email protected](0,10);

logger.warn("from_today_value= "+from_today_value);

for each (var item in xmlPage.forecast.time) {

var row = new O

atbject();

var [email protected](0,10);

row.WindDirection = item.windDirection.@name;

row.WindSpeed=item.windSpeed.@mps;

row.WeatherTemp=parseInt(item.temperature.@value);

row.WeatherHumidity=parseFloat(item.humidity.@value);

row.From =  item.@from;

row.To =  item.@to;

row.Title=xmlPage.location.name+" "+xmlPage.location.country;

//  row.Precipitation=(item.precipitation.@type+" "+item.precipitation.@value)==" "?"NoPrecipitation":item.precipitation.@type;

result.AddRow(row);

}

}

attach image error.png

 
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