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Hello,
How to insert a line at line number 3 of a file
I can do it by awk, but I appreciate it if you can teach me how to do it by sed in place
$ awk 'NR==3{print "New Line with awk"}1' file > newfile
Hi SirDIce,
I was searching for it in the last 24 hours. and I read the link you are providing but it's not working in FreeBSD mostly working under GNU sed
Thanks,
dice@williscorto:~/test % sed -i '' -e '3i\\
this is my new line 3' foo.txt
dice@williscorto:~/test % cat foo.txt
this is my new line 3
> this is my new line 3' foo.txt
sed: 1: "3i\\
this is my new lin ...": extra characters after \ at the end of i command
amr@Z420:/usr/home/amr $
root@Z420:/usr/home/amr # sed -i '' -e '3i\\
? this is my new line 3' foo.txt
root@Z420:/usr/home/amr # cat foo.txt
this is my new line 3
root@Z420:/usr/home/amr #
Can I use the command one time without pressing enter
# sed -i '' -e '3i\\this is my new line 3' foo.txt
because I want to use it in shell script
You can use
re_format(7)
for substitute to matching the null string at the beginning of a line then insert text ending with
\n
you need to test it yourself it must be somethink like
sed -i '' -e '3s/^/line3\n/g' test.txt
for more info read the manual
sed(1)
This is not about sed so a bit off topic, but I also like using
ed(1)
after reading a book on the line editor.
It can be used in scripts.
$ diff -u sample.txt.bak sample.txt
--- sample.txt.bak 2020-11-10 03:42:54.362425000 +0000
+++ sample.txt 2020-11-10 03:42:54.362466000 +0000
@@ -1,5 +1,6 @@
+inserted line
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