报错AttributeError: 'list' object has no attribute 'strip',如何解决?
时间: 2024-05-28 20:07:37
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这个报错的原因是因为你在尝试使用strip()方法对一个list类型的对象进行操作,而strip()方法只能对字符串进行操作。你需要先将list类型的对象转换成字符串类型,然后再使用strip()方法。
例如,如果你有一个列表对象list1,你可以使用join()方法将其转换成字符串类型,然后再使用strip()方法,如下所示:
list1 = [' hello ', ' world ', ' ! ']
str1 = ''.join(list1)
str2 = str1.strip()
print(str2)
输出结果应该是:"hello world !"
相关问题
上述代码报错AttributeError: 'list' object has no attribute 'strip'
非常抱歉,我在之前的代码中犯了一个错误。在提取省、市、区、县、镇时,有可能会出现多个匹配结果,因此返回的是一个列表。你需要对列表中的元素进行处理。以下是修正后的代码:
```python
import re
from pypinyin import lazy_pinyin
def parse_address(address):
# 提取省份
province = re.findall(r"([\u4e00-\u9fa5]+省)", address)
if province:
province = province[0].strip()
address = address.replace(province, "") # 将省份从地址中移除
else:
province = ""
# 提取城市
city = re.findall(r"([\u4e00-\u9fa5]+市|[\u4e00-\u9fa5]+自治州)", address)
if city:
city = city[0].strip()
address = address.replace(city, "") # 将城市从地址中移除
else:
city = ""
# 提取区、县
district = re.findall(r"([\u4e00-\u9fa5]+区|[\u4e00-\u9fa5]+县|[\u4e00-\u9fa5]+市辖区)", address)
if district:
district = district[0].strip()
address = address.replace(district, "") # 将区/县从地址中移除
else:
district = ""
# 提取镇
town = re.findall(r"([\u4e00-\u9fa5]+镇)", address)
if town:
town = town[0].strip()
address = address.replace(town, "") # 将镇从地址中移除
else:
town = ""
return province, city, district, town
def parse_pinyin(address):
pinyin = lazy_pinyin(address)
return "".join(pinyin)
address = "浙江省杭州市西湖区古墩路"
province, city, district, town = parse_address(address)
province_pinyin = parse_pinyin(province)
city_pinyin = parse_pinyin(city)
district_pinyin = parse_pinyin(district)
town_pinyin = parse_pinyin(town)
print("省份:", province)
print("城市:", city)
print("区/县:", district)
print("镇:", town)
print("省份拼音:", province_pinyin)
print("城市拼音:", city_pinyin)
print("区/县拼音:", district_pinyin)
print("镇拼音:", town_pinyin)
```