Hi,

Im trying to encryp using AES 128 CTR but i dont get the same result that online calculators.

Im using this online calculator: https://cryptii.com/pipes/aes-encryption

My code is the next:

uint8_t IVKey[] = {0xDD, 0xF9, 0x11, 0xA6, 0xDD, 0xF9, 0x11, 0xA6, 0xDD, 0xF9, 0x11, 0xA6, 0xDD, 0xF9, 0x11, 0xA6};
	AesDeInit();
	// CTR AES
  hcryp.Instance = AES;
  hcryp.Init.DataType = CRYP_DATATYPE_1B;
  hcryp.Init.KeySize = CRYP_KEYSIZE_128B;
  hcryp.Init.pKey = (uint32_t *)AESKey;
  hcryp.Init.Algorithm = CRYP_AES_CTR;
  hcryp.Init.pInitVect = (uint32_t *)IVKey;
  if (HAL_CRYP_Init(&hcryp) != HAL_OK)
    Error_Handler();
  }

and the AESKey is the next:

const uint8_t AESKey[] =
{0x44, 0x26, 0x44, 0x20, 0x45, 0x6C, 0x65, 0x74, 0x74, 0x72, 0x6F, 0x6E, 0x69, 0x63, 0x61, 0x20
};

My AES function is the next:

int16_t AesEncrypt(char *In,int16_t Len)
	uint8_t Buf[16];
	if (Len & 0x0F)					
		Len+=16-(Len & 0x0F);
	if (HAL_CRYP_DeInit(&hcryp)!=HAL_OK)
		Len=0;
	else if (HAL_CRYP_Init(&hcryp)!=HAL_OK)
		Len=0;
		for (int16_t i=Len;i>0;i-=16)				// Encripta paquete
			if (HAL_CRYP_Encrypt(&hcryp,(uint32_t *)In,16,(uint32_t *)Buf,255)!=HAL_OK)
				Len=0;
				break;
			memcpy(In,Buf,16);
			In+=16;
	return Len;
}

and the string insert into the function is

char Message2[] = {0x50, 0x00, 0x30, 0x30, 0x30, 0x30, 0x30, 0x31, 0x01, 0x03, 0x08, 0x20, 0x00, 0x00, 0x00, 0x00};

The result with the online calculator is: 6c 9d 95 e6 9a 75 ed 03 7c a2 81 80 f9 a6 c3 18

The result that im getting is: c4, b0, c3, 8d, 2d, b2, 5b, 20, 89,75, 57 76, 83, 06, be, 1e

My result is wrong t i dont know what am i doing wrong.

Any suggestion?

Thanks,

Best Regards,

Confirming on-line result with C library here, Decrypting in this case, but symmetrical..

KEY
0000 : 44 26 44 20 45 6C 65 74-74 72 6F 6E 69 63 61 20 D&D Elettronica
0000 : DD F9 11 A6 DD F9 11 A6-DD F9 11 A6 DD F9 11 A6 ................
CRYPT-TEXT
0000 : 50 00 30 30 30 30 30 31-01 03 08 20 00 00 00 00 P.000001... ....
PLAIN-TEXT
0000 : 6C 9D 95 E6 9A 75 ED 03-7C A2 81 80 F9 A6 C3 18 l....u..|.......

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